Someone calculate this theory,

ERRORIST · 2004-12-09 19:17:05

"EARTH THE GIANT PUMP"

Gravity is greater at the poles of the Earth because the Earth is not spinning as much. This why you would weigh more at the poles. At the Equator the Earth is rotating at near 1000kmphr. If you were to have a pipeline with both openings at the same elevation at each location water would flow from the pole to the equator.If we can build a pipeline from the artic ocean to the Fl keys it would be possible to pump very cold water using the Earths rotational velocity as the pump. No electricity needed. Open a valve near the end and cold water would flow to the keys thus weakening hurricanes and perhaps preventing tornados if cool water is sent to the Gulf Of Mexico.Also, How much energy would it be able to produce when not fighting Hurricanes and could that energy be used to launch spacecraft to space??

GCNRevenger · 2004-12-09 21:53:52

You've got to be kidding me...

Since there is no divider between the Arctic and Atlantic & Pacific oceans, why doesn't the Arctic ocean drain and dry up and all its water pool at the equator? Because this force is miniscule compared to the inertias involved.

The friction force alone in your pipe would stop the water dead anyway.

ERRORIST · 2004-12-09 22:07:51

Since there is no divider between the Arctic and Atlantic & Pacific oceans, why doesn't the Arctic ocean drain and dry up and all its water pool at the equator? Because this force is miniscule compared to the inertias involved.

It does pool at the equator and that is why the oceans bulge out at the equator due to the centrifugal forces. But, there is so much water it drains back due to gravity thus creating the ocean currents.

GCNRevenger · 2004-12-09 22:24:00

Which would reach an equilibrium. It doesn't reach an equilibrium because the Sun heats the water which causes the circulation.

"it drains back due to gravity" is exactly why your pipe would have no net flow.

ERRORIST · 2004-12-09 22:35:34

Nope, in the pipe the energy is conserved since it is enclosed. In the ocean it is not thus you have waves and the energy is wasted.

GraemeSkinner · 2004-12-09 22:46:15

Since there is no divider between the Arctic and Atlantic & Pacific oceans, why doesn't the Arctic ocean drain and dry up and all its water pool at the equator? Because this force is miniscule compared to the inertias involved.
It does pool at the equator and that is why the oceans bulge out at the equator due to the centrifugal forces. But, there is so much water it drains back due to gravity thus creating the ocean currents.

There are more forces at work than that of gravity when you are talking of ocean currents. And what of the effect of the moon on your Earth pump?

Graeme

Trebuchet · 2004-12-09 22:53:42

It would be much, much more effective to simply build a dam across the Bering Straits, and power water through one way or the other. Uses much more water, but hey, you could build a rail line on top and connect the whole world (minus Australia)...

Of course, this forgets one small thing: it's stupid and insane, just like the really long pipe. You'd be better off developing some kind of foamy goo to bomb the ocean with and increase surface albedo or lower evaporation if you wanted to harm hurricanes. And if power generation is wanted, there's plenty of other simpler ways of generating much more power.

ERRORIST · 2004-12-09 23:04:12

There are more forces at work than that of gravity when you are talking of ocean currents. And what of the effect of the moon on your Earth pump?

As long as it is submerged during the tides it will flow towards the equator. Calculate the velocity at or near the Keys in Florida?? It reminds me of the vanes on a pumps impellar tossing the water outward due to the centrifugal force. every bit of the ocean is traveling at 1000kmph near the equator but near the poles it is almost stagnet.

John Creighton · 2004-12-10 08:24:07

Hmmm….Weaken hurricanes at the keys while melting ice at the poles. Sounds good.

ERRORIST · 2004-12-10 19:50:02

Nope, not melting ice at the poles at all. What is removed will be replaced by the ocean filling back in. Calculate the velocity of the water going into radius 1,then calculate the velocity of the water as it leaves the tube at radius 2.
Velocity of the water at (North pole) R1=1 Mph. Velocity at (Equator) R2=1,000Mph

GraemeSkinner · 2004-12-10 22:22:40

Nope, not melting ice at the poles at all. What is removed will be replaced by the ocean filling back in. Calculate the velocity of the water going into radius 1,then calculate the velocity of the water as it leaves the tube at radius 2.
Velocity of the water at (North pole) R1=1 Mph. Velocity at (Equator) R2=1,000Mph

Why don't you do the calculations?

Graeme

ERRORIST · 2004-12-10 22:25:14

Don't know all that is involved with it.I don't know the math that well.

Austin Stanley · 2004-12-11 03:36:09

Yet you are SURE it will work!?!

ERRORIST · 2004-12-11 04:43:46

exactly

ERRORIST · 2004-12-11 20:50:37

Where would I start on this problem? Can we work it through as a team effort?

Trebuchet · 2004-12-11 23:01:59

I'd rather stab myself with a spork.

ERRORIST · 2004-12-12 04:53:02

Is a spork a Vulcan fork? What do I need to calculate in this problem to find exit velocity?

MarsDog · 2004-12-12 09:26:02

Water flows downhill.
And, first approximation, it flows into the ocean, assuming lowest point of energy.

The effects you are going to have to calculate have to do with the Sun, Moon, wind, density currents, etc.... Add shorelines and underwater mountains.

John Creighton · 2004-12-12 10:42:35

What you want to do is first look for a free open source climate simulation program.

ERRORIST · 2004-12-12 21:57:18

Yes water flows down hill and plumbers would use a different word than water.The ends of this pipeline that are submerged are at the same elevation under water.The pressure (force) at the pole would be greater than the pressure at the Equator due to the centrifugal force. Difference in pressure = flow.

MarsDog · 2004-12-13 06:26:58

The ends of this pipeline that are submerged are at the same elevation under water.The pressure (force) at the pole would be greater than the pressure at the Equator due to the centrifugel force. Difference in pressure = flow.

If you had a ship, at the Equator, holding the pipe, below the surface; The water under the ship would keep rising till it was in Geosychronous. Good way to launch a spaceship to Mars ?

ERRORIST · 2004-12-13 07:03:20

MarsDog,

What do you mean? Explain further.

MarsDog · 2004-12-13 19:19:43

You would have to increase the http://scienceworld.wolfram.com/physics … ml]angular momentum, so that water could flow to space.

ERRORIST · 2004-12-13 22:27:36

So can you use this formula to calculate the speed of the water exiting the pipeline at the equater?If so what would the formula look like?

ERRORIST · 2004-12-15 07:14:32

How does angular momentum come into effect using this pipeline?

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#1 2004-12-09 19:17:05

Re: Someone calculate this theory,

#2 2004-12-09 21:53:52

Re: Someone calculate this theory,

#3 2004-12-09 22:07:51

Re: Someone calculate this theory,

#4 2004-12-09 22:24:00

Re: Someone calculate this theory,

#5 2004-12-09 22:35:34

Re: Someone calculate this theory,

#6 2004-12-09 22:46:15

Re: Someone calculate this theory,

#7 2004-12-09 22:53:42

Re: Someone calculate this theory,

#8 2004-12-09 23:04:12

Re: Someone calculate this theory,

#9 2004-12-10 08:24:07

Re: Someone calculate this theory,

#10 2004-12-10 19:50:02

Re: Someone calculate this theory,

#11 2004-12-10 22:22:40

Re: Someone calculate this theory,

#12 2004-12-10 22:25:14

Re: Someone calculate this theory,

#13 2004-12-11 03:36:09

Re: Someone calculate this theory,

#14 2004-12-11 04:43:46

Re: Someone calculate this theory,

#15 2004-12-11 20:50:37

Re: Someone calculate this theory,

#16 2004-12-11 23:01:59

Re: Someone calculate this theory,

#17 2004-12-12 04:53:02

Re: Someone calculate this theory,

#18 2004-12-12 09:26:02

Re: Someone calculate this theory,

#19 2004-12-12 10:42:35

Re: Someone calculate this theory,

#20 2004-12-12 21:57:18

Re: Someone calculate this theory,

#21 2004-12-13 06:26:58

Re: Someone calculate this theory,

#22 2004-12-13 07:03:20

Re: Someone calculate this theory,

#23 2004-12-13 19:19:43

Re: Someone calculate this theory,

#24 2004-12-13 22:27:36

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#25 2004-12-15 07:14:32

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