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Suppose we approached terraforming Mars the way we'd heat a building. Lets say we dotted the surface of Mars with nuclear reactors, we mined out enough Uranium and started splitting Uranium atoms to produce heat, and we space the heaters just so as to heat most of Mars' surface to room temperature, this would melt the ice caps, and eventually much of the permafrost thicken the atmosphere so liquid water could be stable. So we keep on mining for Uranium and also split the plutonium that gets produced in such reactions. I suppose some of the fission reactors would be used to power robots to construct more fission reactors and more robots to build more fission reactors, we keep on doing this until Mars reaches a comfortable temperature and the atmosphere thickens. Mars already receives enough sunlight for photosynthesis, the heaters are simply employed to keep the plants from freezing, it supplies that extra energy that the Sun does not supply for Mars. The great thing about these heaters is we can start small by building one.
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These could be linked into a coil to cause the magentic field to be re-enforced to allow for the atmosphere to be grown....
What would the cooling agent be since there is no body of water for the reactors to use?
What mass of parts must we deliver to complete the insitu resource built units?
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NUCLEAR GRAVITATION FIELD THEORY
Chapter X: Quantum Mechanics, General Relativity, and the Nuclear Gravitation Field Theory
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NUCLEAR GRAVITATION FIELD THEORY
Chapter X: Quantum Mechanics, General Relativity, and the Nuclear Gravitation Field Theory
A rather long article, but what relevance is nuclear gravitation to terraforming? I know an elementary particle is rather dense, and if you can get up right next to a proton, then the gravitational field of a proton is rather significant. Now the question, how many dimensions does space have at such a small scale, is it three or four, or maybe twelve as string theory suggests? That means the gravitational constant is different over more than 3 special dimensions, the more dimensions there are, the higher the gravitational constant could be. So if their are more than three dimensions, then the strong force could equate to gravity and be the same force. I don't know how you would terraform Mars with this however.
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Teraforming Mars requires radiation shield ( ie van radiation belts, plasma bound to earth via gravity) an atmosphere that is not lost due to solar winds and by heating mars its now on its way to being teraformed which nuclear reactors would provide.
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Until you run out of atoms to split.
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