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#51 Re: Interplanetary transportation » Reusable Rockets to Orbit » 2011-12-09 16:37:53

Hop
GW Johnson wrote:

When you talk about "gravity loss",  you are really talking about the effects of that non-constant vertical weight vector,  integrated over time. 
GW

This my model:
JumpGravLoss.jpg

All these things are constantly changing

a the gross acceleration vector
alpha, the angle from horizontal
ah, the horizontal component of a
av, the vertical component of a
gravity changes with altitude
and so called centrifugal force grows with the (horizontal velocity)^2/r

Integrating all that is beyond my abilities. But I did break it into chunks and do a Riemann sum. Saturn V launched from a 100 km altitude.

For most of it I kept the acceleration vector vertical enough to meet or exceed the net downward pull. Over time it gets more horizontal.

Rune wrote:

...he insists and insists about gravity loss, and he's right about that, it IS a function of time. It could be minimal if your rocket shoots up at 20G's, or it could multiply delta-V several times if you choose to go up slowly and majestically, like the alien ships in sci-fi shows.

You're describing well what I have in mind, perhaps more clearly than my attempts.

Rune wrote:

Thus, total delta-v to orbit, by definition, is at least in part a function of flight time, and therefore T/W. Figure out your flight time, and you have your gravity loss, no need to estimate (only since mass is a variable, so is gravity loss/s, and therefore getting the gravity loss involves integrating a differential equation, no two ways about that).

Wish I could solve it as an integral. But I've been modeling by brute force numeric method (see spreadsheet above).


Rune wrote:

Oh, and T/W of an engine, for the same engine, IS proportional to the fuel's density (a few engines can run several fuels, russian experiments with methane on kerolox engines jump to mind). Or to be more precise, with it's molecular weight, and directly proportional at that. The rest (which you can approximate to a fixed coefficient and not go too wrong about it) is the engine cycle that you use, and you weight efficiency (a function of the chosen material, and those don't really change that much)... with clever designing assumed, of course. That's why H2/LOX has such low T/W no matter what engine cycle you use.

I'm not sure of these. I can see how molecular weight is related to density of a gas, thrust, and ISP. But I believe most of the propellant densitiess Josh lists are for liquids. Just comparing the density of water and kerosene suggests to me this doesn't work for liquids.

Rune wrote:

On the actual topic of the thread, reusable rockets to orbit... I think we should open up a new one to discuss Musk's idea for turning F9 into F9"R"... I suppose you have seen the video and heard him talk about it? It looks... well, it made me grin like a stupid. And the words "like god and Robert Heinlein intended them to" jumped to my mind. Also, why has no one actually tried to do something like that before?

Musk's Grasshopper videos are very exciting. For the first stage, I am wondering if it could land on an island east of the launch site. That way the first stage could pick up some horizontal velocity and still be recovered relatively unscathed.

I am skeptical, though. The video seems to indicate some of the re-entry velocity is shed by aerobraking and some by using propellant as reaction mass. Using propellant to slow down adds to the delta V budget and makes an already difficult mass fraction even more difficult. At this point I'm giving Musk less than even odds of pulling this off.

JoshNH4H wrote:

Vo=7800 m/s
Vu=sqrt(2*2.81e6)=2,370 m/s
Dg=~2/3*300 s*9.8 m/s^2=1,960 m/s*
Da=150 m/s

For Vu you're using difference in potential energy between 0 and 300 km altitude. If you are going 300 km straight up (as in your original scenario), this would be accurate.

But an orbit's energy is the sum of both kinetic and potential energy. And a more practical trajectory would pick up kinetic energy along the way.

Let's say our rocket achieves a circular orbit at 100 km altitude. It doesn't want to stay there as the tenuous atmosphere at that altitude will degrade its orbit over time. How much will it take to reach a more enduring 300 km altitude circular orbit? The potential energy difference between these two orbits is 1.84 MJ/kg. But the difference between their total energies (that is potential and kinetic energy) is exactly half that -- .92 MJ/kg. Rather than achieving an additional 200 km altitude with a vertical burn, it's better to do a horizontal perigee burn followed by another horizontal apogee burn to circularize.

In reality a rocket might achieve a fraction of orbital velocity at 100 km. But even in this case, it still has kinetic energy.

Your method of assessing energy to reach an altitude relies solely on potential energy and ignores kinetic energy.

#52 Re: Interplanetary transportation » Reusable Rockets to Orbit » 2011-12-06 21:09:27

Hop
JoshNH4H wrote:

Wrt the thrust-to-weight of a rocket, when did I ever suggest that gravity drag was insignificant?

Your propellant table looks at ISP and density. No mention of thrust to weight. If you regard gravity drag as significant, your tables should also look at T/W.

JoshNH4H wrote:

For my model of Delta-V to orbit, both could be about a a km/s or two and the final number would still end up being what it is.

So 2.4 km/s for potential energy and 2 km/s for gravity loss? Sounds like you're still trying to get a vertical velocity vector with magnitude around 5 km/s.

JoshNH4H wrote:

The relation between the two is of course not quite as linear or direct as you portray it,

As I portray it? Recall that the first stage going straight up and coming back down to the same launch pad is your image.

You imagined this first stage making a 5.25 km/s vertical velocity vector which is added to a 7.9 km/s horizontal velocity vector to get 9.4 km/s hypotenuse for your total delta V budget.

JumpBoyVectors.jpg

I stuck with your image since it was familiar to you. I noted a vertical ascent incurs gravity loss.

A 9.8 m/s^2 vertical acceleration is killed by gravity. It gives you 0 km/s. But this acceleration still consumes propellant, so you have to include the vertical a * t lost to gravity in your delta V budget.

Your mistake is assuming the lost vertical a * t gives a vertical velocity vector that you can add to the horizontal velocity vector. Doesn't work when velocity vector has magnitude zero.

Gravity loss can be arbitrarily large. You can make it as big as you want by increasing payload mass thus reducing thrust to weight ratio.

If you do a slow vertical ascent over 612 seconds, gravity loss is 6 km/s. Does that mean you can turn sideways, do an 8 km/s horizontal burn, and claim the 10 km/s hypotenuse as your delta V budget? No. Your total delta V budget would be 14 km/s.

Actual ascent trajectories typically start vertical and turn horizontal over time. If your acceleration vector is alpha degrees from horizontal, cos(alpha)|a| is the magnitude of the horizontal component and sin(alpha)|a| is the magnitude of the vertical component. The magnitude of the net vertical component would be sin(alpha)|a| - g + (w^2 * r), where w is angular velocity in radians and r is distance from earth's center. g is GM/r^2, of course.

In this case, the vertical acceleration component lost to gravity also doesn't add to vertical velocity. Even with this more accurate and complicated flight path, your model is wrong.

#53 Re: Interplanetary transportation » Reusable Rockets to Orbit » 2011-12-06 12:49:29

Hop
JoshNH4H wrote:

As I suppose you missed in my last post, I mentioned that the difference was presumably due to the difference in orbital speed between a 0 km orbit and a 300 km orbit.

Which is different from what you wrote earlier:

JoshNH4H wrote:

To go from the surface of the Earth to 300 km requires an input of 2.94 MJ/kg.  The force for this energy ha to be applied straight up.  Therefore, as per implicit convention, we use the equation Esp=.5*v^2 where Esp is in J/kg to calculate a velocity of 2,425 m/s (It will actually be slightly less than this because I did not account for the difference in gravity between .  If you do the energy calculations, the difference in energy between 8.1 km/s and 7.1 km/s is very similar to that number

Which is flat out wrong. First some minor nitpicks: the potential energy is 2.81 MJ/kg, not 2.94 MJ/kg. And the 7.1 km/s is a typo, it should have been 7.9 km/s.

More importantly, the energy difference between 7.9 km/s and 8.1 km/s is nowhere near 2.81 MJ/kg.

A good response would have been for you to admit you're wrong.

That you then say something else and pretend you never wrote the above is very disappointing.

#54 Re: Interplanetary transportation » Reusable Rockets to Orbit » 2011-12-06 07:44:28

Hop
Terraformer wrote:

Welcome back, GW. It's a pity all the threads are gone that had a lot of good discussions about Ramjets.

Nasaspaceflight.com has numerous threads on related topics. If you use search strings like ramjets, scramjets, Skylon, you will find many discussions.

One such discussion is The airbreathing space launch thread.

#55 Re: Interplanetary transportation » Reusable Rockets to Orbit » 2011-12-06 07:28:22

Hop
JoshNH4H wrote:

So:  I promised an analysis of the fuels involved in my hypothetical space rocket.  There are two basic schools of thought on this- there's the school of thought suggesting that dense, somewhat lower Isp propellants are advisable; on the other hand, there are also people who think that we should just bluntly attack the problem by raising Isp as high as possible to minimize the mass ratio. 

This represents two different ways of looking at the issue, which are best described with two different figures of merit.  The "dense propellants are better" school will tend to point at a figure of merit that is something like "Mass Ratio/Density of propellant,"

Higher ISP propellants have lower thrust.

If you have anemic thrust, it will take you longer to achieve altitude and you thus incur greater gravity losses.

An example is ion engines. Very good ISP. But T/W < 1. It would take forever to reach altitude and gravity loss would be infinite.

But since you're predisposed to thinking gravity loss is inconsequential, you likely won't consider consider stuff like thrust to weight ratio.

#56 Re: Interplanetary transportation » Reusable Rockets to Orbit » 2011-12-06 07:16:35

Hop
JoshNH4H wrote:

7100 m/s was a typo, my mistake.

You admit this mistake and then ignore the correct numbers.

Again, the difference between 8.1 and 7.9 km/s is 1.6 MJ/kg.

This is NOT the same as the potential energy difference between earth's surface and a 300 km altitude, 2.81 MJ/kg.

JoshNH4H wrote:

That's an incredibly dismissive way to talk about the scientific method.

You're trying (unsuccessfully) to get the numbers to meet your expectations.

This is not the scientific method.

I find it incredibly arrogant that you characterize dismissal of your models as dismissing the scientific method.

#57 Re: Interplanetary transportation » Reusable Rockets to Orbit » 2011-12-05 11:12:13

Hop
JoshNH4H wrote:

I'm not quite sure I can explain this any better than to repeat myself in saying that ⌂V is not a scalar and is not a state function.  Energy, on the other hand, is.  To go from the surface of the Earth to 300 km requires an input of 2.94 MJ/kg.

This from potential energy?.  I get 2.81 MJ/kg.

JoshNH4H wrote:

The force for this energy ha to be applied straight up.  Therefore, as per implicit convention, we use the equation Esp=.5*v^2 where Esp is in J/kg to calculate a velocity of 2,425 m/s (It will actually be slightly less than this because I did not account for the difference in gravity between .  If you do the energy calculations, the difference in energy between 8.1 km/s and 7.1 km/s is very similar to that number (though given that there is a very limited number of sig-figs here there is a significant margin of error).

((8100 meters/second)^2) / 2 = 32805000 (meters/second)^2
((7100 meters/second)^2) / 2 = 25205000 (meters/second)^2

32805000 - 25205000 = 7600000

The specific energy difference between 8.1 km/s and 7.1 km/s is 7.6 MJ/kg. Not remotely similar to 2.94 MJ/kg.

I don't know where you got 7.1 km/s, though.

The specific energy difference between 7.9 km/s and 8.1 km/s is 1.6 MJ/kg. Also not remotely similar to 2.94 MJ/kg.

I don't have time to look at your math. Your approach seems to be to look at the numbers and then try to guess an equation that will give an answer that matches. When you derive your equations from first principles, I will give them more attention.

#58 Re: Human missions » Is space within our reach? » 2011-12-04 16:04:38

Hop

Thank you for some interesting links, Spacenut.

SpaceNut wrote:

Hop I believe these links will highlight what you see in the insitu processing to get the material ready to be used.

Major Lunar Minerals

As you smelt the ore of

"anorthite" mineral consisting of 20% aluminum (chemical symbol Al), calcium (Ca), silicon (Si) and oxygen (O), with a chemical formula of CaAl2Si2O8. The smelter's job is to split all that up to produce pure aluminum metal, and optionally calcium metal, free oxygen, "silica" glass (SiO2), and perhaps pure silicon.

For each metal that we seek there is a different process to how to seperate it from the raw ore that is dug, mined or gathered.

As you know, Tsiolkovsky's rocket equation is very prominent on my radar screen. That is why lunar water is the resource I'm most excited about.

But a major obstacle is energy to crack water into the hydrogen and oxygen propellant. Given power sources of plausible mass it is hard to crack water at the rates an orbital propellant market would demand.

And aluminum is much worse. Here on earth we dissolve alumina in molten halogen salts and then split the oxygen from aluminum by electrolysis. An extremely energy intensive process. If limitations to GLOW and power sources with low specific power are headaches for cracking water, they're much worse for mining aluminum.

Mining iron, titanium and other metals are also energy intensive. They do have an oxygen byproduct, though.

So one of the things I hope for are power sources with lots of watts per kilogram. Not only would this make ISRU more plausible but it would improve the performance of ion engines.

If we did get enough power on the moon to mine aluminum, silicon and other minerals, we could start making solar panels from ISRU materials. Then the lunar power constraints would be slain. But this is a very ambitious project.

SpaceNut wrote:

Lunar Maters LLC

Acquisition and sale of platinum group metals (PGMs) extracted from Ni-Fe asteroid fragments collected from the lunar surface constitutes the flagship product line for Lunar Materials

I like this. Some of the best metal ores in our solar system are asteroids that come from differentiated bodies. These have better metal ores than found in planetary crusts. And it's possible that some metallic meteorites lie in the basins of lunar craters.

But lunar platinum couldn't be viable unless we had more economical transport to and from the moon. Again, volatiles are a prerequisite.

SpaceNut wrote:

It is felt that it would not be profitable to mine and export the moon for Earths mineral sources.
Mining the Moon for Rare Earth Elements - Is It Really Possible?

http://rareearthelements.us/yahoo_site_ … 48_std.gif

A few things this article brings up are the severe temperature swings and lack of volatiles. Both are much less of an issue at the lunar poles. Does the lunar KREEP extend to the poles? I don't know.

One of the hidden costs is environmental harm that rare earth mining inflicts. Not an issue on the moon. One of the harmful by-products is thorium. Possibly a lunar energy source. Kirk Sorensen has been trumpeting energy from thorium.

If luna infrastructure had enough power to make propellant and power rail guns, transportation costs would be cut a great deal. Possibly this would enable export of rare earths. But this a long term goal.

#59 Re: Human missions » Is space within our reach? » 2011-12-04 15:24:53

Hop
SpaceNut wrote:

I see from the post that many a what if changes the equation....
Such as the intake of fuel from other means in any of the steps of delta v changes.
I recall the air in take of the first stage to orbit as one such item as it changes the mass of the rocket equation.

You're right, getting oxidizer as we pass through the atmosphere is one of the possibilities I hadn't looked at.

I was enthusiastic about scram jet lower stages for a time. Then some aerospace engineers whose opinion I respect pointed to what they regard as show stoppers.

Then Skylon came along. I was giving Skylon even odds. But at the moment I'm giving them less than even odds. If the Skylon boys do pull it off, it will be a major game changer.

Most (if not all) of the what ifs I mentioned are still open to question -- they're not done deals. I have no certainty the case for space resources can close. But naysayers like Stross or Murphy have no certainty either. And folks like Murphy and Stross greatly exaggerate the obstacles, in my opinion.

#60 Re: Human missions » Is space within our reach? » 2011-12-03 17:32:21

Hop
Terraformer wrote:

I like it. Only, I seem to recall Luna has vauable metals which could be easily gathered, I seem to recall, which would be cheaper and easier to get than the asteroids...

That's something I don't know much about. If you run across any articles on lunar metals, I hope you'll share them.

#61 Re: Human missions » Is space within our reach? » 2011-12-03 15:20:46

Hop
Terraformer wrote:

"I had never worked through these computations before, and took my typical approach of estimating obvious, brute-force solutions to a problem."
Therein lies the problem... he used what seemed obvious to him, ignoring all the much easier things that can be done.

You sum up the major flaws with his essay quite nicely.

Terraformer wrote:

As a result, his post should be quite easy to refute. Just point out about Luna.

That is what I have done. See Murphy's Mangled Math.

#62 Re: Human missions » Mission One: a one way ticket to Mars? » 2011-12-03 15:14:41

Hop
Terraformer wrote:

@Hop - no need to make them mine the resources and plonk them in Siberia;

To better simulate Mars' hospitable environment, it would be better to put them in Hawaii?

Terraformer wrote:

just give them what they could easily access on Mars and make a much easier to do experiment. It's the refining that's the main issue, after all...

What they could easily access on Mars is mixture of dirt and ice, also known as permafrost. Lots of that in northern Siberia.

#63 Human missions » Is space within our reach? » 2011-12-03 13:47:35

Hop
Replies: 41

Tom Murphy is a physics professor whose Do The Math blog urges conservation of resources. He argues the earth is finite, therefore our rate of consumption can't continue to grow as it's done in the past.

His Stranded Resources argues space resources will remain beyond our grasp.

He regards attempts to settle or use space as wasted effort that could be better spent learning to live within our means.

I believe his view is becoming more widespread. If so, it will become even harder to drum up popular support for human spaceflight.

#64 Re: Human missions » Mission One: a one way ticket to Mars? » 2011-12-03 11:36:58

Hop
JoshNH4H wrote:

Hop- I think that you're overusing the word "need," as well as being overly pessimistic

One way to convince me would be to demonstrate your optimism is plausible.

Things like the Mars simulated mission fall short.

Rather than live in a tin can for years, they should plonk some people and equipment of plausible mass in northern Siberia. From this single location a handful of people would mine all the minerals they need and then use them to manufacture bulldozers, growlights, wires for power transmission, airlocks, air filters, grow food, make clothes, air filters etc.

Not only should they build a Walden pond in this hostile location, but a Walden Pond that has the infrastructure to manufacture heavy equipment, plumbing, etc..

Until you can demonstrate this, your argument is furious handwaving.



JoshNH4H wrote:

...As primary exports, I think we would be looking perhaps at precious metals,

Mars would export gold or platinum? Sorry, this business case doesn't close by a long shot. Your expense would probably exceed your revenue by three or four orders of magnitude.

JoshNH4H wrote:

but primarily at intellectual property exports will be big.

So a small population could sit down on Mars and come up with multi-trillion dollar ideas?

If the potential Mars settlers could do this on Mars surface why don't they just simply do this while they're still here on earth? This would solve the problem of funding a Mars mission.

#65 Re: Human missions » Mission One: a one way ticket to Mars? » 2011-12-02 15:09:52

Hop
JoshNH4H wrote:

Hop- I am well aware of the complexity of  the infrastructure behind modern life.  However, Mars has several advantages when it comes to building an economy that can make a closed loop.  Of things that I can think of right now, these are:
The colony can be located wherever is convenient: This minimizes transport costs.  The colony could conceivably be located within a few kilometers of significant concentrations of important source materials

That colony would need to be near water. AND Copper. AND Iron. And other minerals. Get back to me when find a location close to high grade deposits of every mineral you need.

A lot of our plastics come from petroleum. The Martian base should also be close to a petroleum reservoir.

If you want several Mars bases neighboring different mineral ore bodies, then you need transportation between bases.

I see beautiful illustrations of Mars mines, underground dwellings and Mars infrastructure. But no heavy equipment. Are we sending Cat heavy equipment to Mars? As well as replacement parts for the backhoes, cranes, etc? Are these in the Mars Direct payloads? Are we going to grade roads by giving astronauts picks, shovels and rakes?

JoshNH4H wrote:

The colony does not need to have an economy that is 100% closed.  It is my contention that the closer you get to full closure the harder it gets to increase your degree of closure.

Here we agree. Almost no earth population is self sufficient. Walden Ponds are very uncommon. Most nations, cities, etc. survive by trade.

But what export does Mars have? Given a 5 km/s gravity well, launch windows each 2.14 years and 8 month trip times, an export that achieves ROI becomes extremely unlikely.

JoshNH4H wrote:

The colony does not need yup have an economy as complex as that of Earth.  I would expect that the Mars colony would not be a very consumerist society and while the colony was small it could be expected to have a minimum of consumer goods.  Similarly, there will be a definite pressure on manufacturers to keep to a relatively narrow suite of materials and keep to fairly simple designs where possible.  This brings me to my next point:

While Martians will be living spartan life styles, they will still need extensive infrastructure to keep them alive.

JoshNH4H wrote:

The marian economy will be designed from scratch, probably before the   first colony is even set up.  This gives a huge advantage as different sectors of the economy will tend to interact logically and not be subject to wasteful replication of capabilities or economic instabilities caused by significant imbalances in production.

In other words a planned economy will do better than a free market? This hasn't been demonstrated to my satisfaction. You're deviating off topic here.

#66 Re: Interplanetary transportation » Reusable Rockets to Orbit » 2011-12-02 14:40:09

Hop
JoshNH4H wrote:

Hop- I am not arguing that your math was done incorrectly.  I have full faith in your ability to plug into the vis-viva equation.  My argument is that the vis-viva equation is irrelevant in this situation because the rocket does not start off in orbit.

You continue to miss my point.

You're trying to assess various factors that add to the delta V for getting to orbit.
We've discussed 1) Air drag, 2) gravity loss, and 3) change of energy for a higher altitude orbit.

Adding .2 km/s to a 6378 km circular orbit would boost it's energy to that of a 6678 km radius circular orbit. This exercise of comparing two circular orbits is to show show something about 3).


JoshNH4H wrote:

As I said before, delta V is not a scalar and not a state function.  The delta V required to get to 300 km is different if you're already moving at some velocity.  This is more or less basic kinematics.  It should be no surprise that the equations governing the behavior of orbiting objects are not relevant when the objects involved are not in orbit.

Revisiting the horizontal launch track on an airless earth. In such a scenario payloads could be launched with virtually no gravity loss and no air drag loss.

Starting from velocity = 0, 7.9 km/s would suffice to put an object in a 6378 km radius low circular orbit.

Starting from velocity = 0, 8.1 km/s would suffice to put an object in a 6678 km radius low circular orbit.

JoshNH4H wrote:

I estimated before that the actual delta V to orbit is approximately equal  (it is my guess that for an intelligently designed trajectory it will actually be somewhat less than this) to the geometric mean of the linear sum of all delta V components and the sum of the components when they are added as vectors.

The acceleration lost to gravity over time doesn't give you a vertical velocity vector whose foot you can place on the head of a horizontal vector to give you a 9.4 km/s hypotenuse. This wrong model is what gave you 5.25 km/s to get above the atmosphere.

#67 Re: Interplanetary transportation » Reusable Rockets to Orbit » 2011-12-01 23:08:01

Hop
JoshNH4H wrote:

Hop- Your calculation for the delta-V required to get from the Earth's surface is simply not correct.  Or at least, given the convention of what the delta-V from one point to another is and the context of this discussion your statement that the delta-V from the surface to LEO altitude is .2 km/s
(I don't like to say that you are outright wrong when you are not technically incorrect and there is nothing wrong with your math).

If you want to try doing the math, a helpful tool is the vis-viva equation:

v^2 = Gm(2/r - 1/a)

G = gravitational constant
m = mass of earth
r = satellite's distance from earth's center
a = semi major axis of orbit.

With that you can determine speed at perigee and apogee of an elliptical orbit.

JoshNH4H wrote:

This goes back to when I said that delta-V is not a state function:  It matters what order you do it in.  If you get the tangential velocity first, then yes the delta-V is .2 km/s.  If you're launching with an initial speed of zero (as rockets have a tendency to do), then the delta-V is most certainly not .2 km/s

Try using the Vis-Viva equation to answer these 4 questions:

What is the velocity of a circular orbit having radius of 6378 kilometers?

Given an elliptical orbit with a 6378 kilometer perigee and an 6678 kilometer apogee,
What is the velocity at perigee?
What is the velocity at apogee?

What is the velocity of a circular orbit having radius of 6678 kilometers?

JoshNH4H wrote:

It is a matter of potential energy.  If you're already moving at 7.9 km/s, an increase in velocity of .2 km/s will result in an increase of energy of 1.6 MJ/kg.  To get that increase starting from zero m/s, you need to be moving at 2.4 km/s.  This is the real delta-V to that altitude which must be considered by someone designing a rocket.

I stipulated the rockets are launched from a horizontal track on an airless world. This exercise is to show what happens when you have zero gravity loss and zero air drag. If you believe I was describing the real delta V someone designing a rocket deals with, you should read more carefully.

Regarding your argument using potential and kinetic energy...

The specific energy (energy per unit mass) of a satellite is

E = v^2/2 - Gm/r

You may recognize the expressions for kinetic as well as potential specific energy.

If you did the 4 vis-viva exercises above, you should have a good idea how to find v.

Given a circular orbit with 6378 kilometers radius, what is E?

Given a circular orbit with 6678 kilometers radius, what is E?

Now take the velocity of the circular orbit with radius 6378 kilometers. Add .18 km/s to this velocity. The object's distance from earth's center is still 6378 kilometers. What is the E of this orbit? How does this E compare to the E of the circular orbit with a radius of 6678 kilometers?

JoshNH4H wrote:

Air drag is generally not huge, but it's not nothing either.

Saturn V had air drag losses of 150 fps. That's about 50 m/s. See page 2 of A Study of Air Launch Methods for RLVs

JoshNH4H wrote:

Gravity drag also appears to be relatively small.

Relative to what? For the Saturn V, gravity loss was about 1500 m/s. This differs from the air drag loss by about a factor or 30.

#68 Re: Interplanetary transportation » Reusable Rockets to Orbit » 2011-12-01 18:18:28

Hop
Terraformer wrote:

Do you guys not use SUVAT notation in America?

(Googling...) You just showed me something new.

#69 Re: Interplanetary transportation » Reusable Rockets to Orbit » 2011-12-01 17:58:51

Hop
JoshNH4H wrote:

... there are other losses beyond simply increasing the potential energy of the system; note that I put gravity drag and the ⌂V required to reach orbital altitude as different things.  Gravity drag is the additional delta V you need when the rocket is accelerating, to keep it in the air.  There is of course also air drag.

In an airless earth, orbital velocity could be achieved on a horizontal track.

An elliptical orbit with a 0 km altitude perigee (in other words, on earth's surface) would have perigee velocity of 8 km/s and an apogee velocity is 7.64 km/s. .1 km/s suffices to circularize at apogee.

So total delta V budget would be 8.1 km/s for achieving a 300 km altitude circular orbit. A circular orbit at 0 km altitude is 7.9 km/s. So without gravity loss or air drag, the extra expense of a 300 km altitude orbit (vs a 0 km altitude orbit) is .2 km/sec.

In most actual launches, loss from air drag is negligible. Especially if it's a big rocket.

Most of the penalty is gravity drag suffered during vertical ascent.

#70 Re: Human missions » Mission One: a one way ticket to Mars? » 2011-12-01 13:15:00

Hop
Grypd wrote:

Of course technology is advancing with the possibility of 3D printers being able to make everything that is needed but of course they do require supplies and power to work so...

Still a long time before that happens.

Here's a 3D printer for metals objects. Lays down a layer of stainless steel powder. Then a binding agent (doesn't specify what binding agent). Then lifted out of the powder, heated and cured infused with bronze.

So three feed stocks: stainless steel, binding agent, and bronze. The feedstocks still need to mined from diverse places.

It's rough. Minimum detail size 1 mm. Doesn't specify how strong it is.

A typical product at Home Depot is made of different materials: copper, aluminum, glass, plastic, silicon are common. Is there one 3D printer that can accomodate diverse feedstocks?

When I see a 3-D printer that can print out working spark plugs as well as staplers, I'll might regard it as a substitute for our extensive manufacturing infrastructure.

And the materials for the feedstocks would still need to be mined.

#71 Re: Human missions » Mission One: a one way ticket to Mars? » 2011-12-01 10:48:46

Hop
JoshNH4H wrote:

Glandu- You make a good point about complete self-sufficiency; however, Mars does have certain advantages on that front compared to most earth societies.  They do, after all, have an entire planet with which to work.  That planet has just about all of the resources needed for an industrial civilization somewhere on its surface.  The manufacturing base might not be sufficient to make things like semiconductor chips and super-fancy high precision parts, but it should be enough to make relatively simple brayton turbines and the like.  The colony has to be self-sufficient, but it does not necessarily need to be an autarky.

I believe you're suffering from the Home Depot syndrome.

It's so convenient to buy something at Home Depot that it's easy to forget it's made with minerals mined from diverse mines, components made by diverse factories, all linked by an extensive transportation infrastructure.

#72 Re: Interplanetary transportation » Reusable Rockets to Orbit » 2011-12-01 10:32:18

Hop
JoshNH4H wrote:

It is a vector that is a combination of vertical and horizontal components.  The horizontal component is Vorbit, 7800 m/s.  The vertical component is a combination of the increase in potential energy, gravity drag (which is separate from potential energy), and air drag, which can be approximated as being primarily vertical because rockets try to get out of the dense lower atmosphere quickly to reduce it, and this involves flying vertically.  Doing the reverse vector addition assume that the "scalar" delta V to orbit was 9,400 m/s, I get that the vertical component of this delta V is 5,250 m/s.

I'm guessing your mental image looks something like this:

JumpBoyVectors.jpg

But in reality you don't get the 9.4 length by adding a 5.25 up leg to a 7.8 sideways leg.

A vertical ascent is done to get above the troposphere as quickly as possible. Typically the vertical ascent takes around 3 minutes.

During vertical ascent, gravity accelerates it down 9.8 meters/second^2. I'll round that to 10 meters/second^2 to make calcs easier.

During 3 minutes of vertical ascent your gravity loss is 180 seconds * 10 meters/sec^2. Which is 1800 meters/sec or 1.8 km/s.

At the top of the vertical ascent rocket speed is usually around zero. When altitude is achieved, the rocket turns sideways for the major horizontal burn.

#73 Re: Human missions » Mission One: a one way ticket to Mars? » 2011-11-30 10:18:57

Hop
JoshNH4H wrote:

Actually I think the idea of a one way mission is quite practical.  Start a base right off the bat andquickly transition to a self-sufficient colony.

NASA as well as politicians have become extremely risk adverse. This extremely expensive endeavor would likely become a suicide mission. You have a doable plan for lobbying congress? No it is not quite practical. Utterly impractical, I would say.

Zubrin's been trying for decades to get commitment to manned Mars missions -- with no success. But getting political support isn't the hardest part. Quickly transitioning to a self sufficient colony will be much harder.

#74 Re: Terraformation » Creating a (small) Lunar atmosphere » 2011-11-29 07:43:53

Hop
Terraformer wrote:

I don't think the reserves are going to be sufficient for making an atmosphere, even a small one...

What about the possibility of gas pockets being formed by volcanic activity early on in Luna's existence?

http://blogs.airspacemag.com/moon/2011/ … a-gas-man/

#75 Re: Terraformation » Creating a (small) Lunar atmosphere » 2011-11-28 10:24:40

Hop
JoshNH4H wrote:

Hop and Midoshi-

Given that Terraformer specifically stated that this was more assuming that we had already decided that we wanted to aeroform the moon, I figured I would leave those details out.  In reality, terraforming would probably rid the moon of its meager concentrations of volatiles and minimize the benefit of aeroforming the the first place; this would of course be negated if you use comets.

Anyway, back to the topic: I'm not sure which is more practical between asteroids and soil burning.  I have a feeling that asteroids are better.  However, there is perhaps something important to keep in mind when the atmosphere you're looking for is that small: Water's vapor pressure at room temperature is 23 mb.  Sending just hydrogen and allowing it to react with the lunar rocks upon impact is a lot cheaper in terms of mass sent to the Moon; Since water is quite a good greenhouse gas, perhaps in combination with a few other GHGs (methane, ammonia, perhaps?), the planet could remain at some equilibrium with a significant amount of atmosphere in the form of water vapor.

Here Chris McKay suggests strapping "a quartet of 5000 MW nuclear thermal rocket engines" to a comet for Mars terraforming. That's 20 giga watts. The very large Palo Verde Nuclear Power Plant in Arizona is about 3 gigawatts. McKay's NTR rockets would take the power 6 Palo Verde plants.

If you're using the comet substance for reaction mass, you need a way to get the comet's substance to the NTR's rocket chamber. This entails setting up a mining infrastructure on the comet as well as transportation infrastructure to deliver the mined volatiles to the NTR's rocket chamber.

A mammoth engineering project on an object in the outer solar system.


Real estate on a planet is measured in area. Temperature and pressure prohibit burrowing too deep into a planet, so accessible resources are also confined to a planet's surface.

The surface area of the small bodies is many, many times that of the rocky planets and large moons. Not only that, but the entire volume of a small body is reachable.

If we terraformed the moon and Mars, that might double our living area. If we developed the asteroids, humanity's living space could be increased millions of times.

The time and effort crashing small bodies into a planet or large moon would be better spent developing the small bodies.

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